Slicing
sliceO
The circular equivalent of slice.
Given the definition of circular sequence, a slice can contain more elements than the sequence itself.
Example
Seq(0, 1, 2).sliceO(-1, 4) // Seq(2, 0, 1, 2, 0)
Compared to standard
In the same example the standard version behaves differently, it is equivalent to slice(0, 2), does not return the “unrolled” slice.
Seq(0, 1, 2).slice(-1, 4) // Seq(0, 1, 2)
indexOfSliceO
The circular equivalent of indexOfSlice.
Given the definition of circular sequence, a slice can contain more elements than the sequence itself.
Example
Seq(0, 1, 2).indexOfSliceO(Seq(2, 0, 1, 2, 0)) // 2
Compared to standard
In the same example the standard version behaves differently, cannot find the “unrolled” slice.
Seq(0, 1, 2).indexOfSlice(Seq(2, 0, 1, 2, 0)) // -1
lastIndexOfSliceO
The circular equivalent of lastIndexOfSlice.
Example
Seq(0, 1, 2, 0, 1, 2).lastIndexOfSliceO(Seq(2, 0)) // 5
Compared to standard
In the same example the standard version behaves differently, does not find the slice containing the last and first elements.
Seq(0, 1, 2, 0, 1, 2).lastIndexOfSlice(Seq(2, 0)) // 2
segmentLengthO
The circular equivalent of segmentLength.
Example
Seq(0, 1, 2).segmentLengthO(_ % 2 == 0, 2) // 2
Compared to standard
In the same example the standard version behaves differently, does not find the segment containing the last and first elements.
Seq(0, 1, 2).segmentLength(_ % 2 == 0, 2) // 1
containsSliceO
The circular equivalent of containsSlice.
Given the definition of circular sequence, a slice can contain more elements than the sequence itself.
Example
Seq(0, 1, 2).containsSliceO(Seq(2, 0, 1, 2, 0)) // true
Compared to standard
In the same example the standard version behaves differently, does not find the “unrolled” slice.
Seq(0, 1, 2).containsSlice(Seq(2, 0, 1, 2, 0)) // false